Rodent Wars Forum

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3 in = 0.0762 m

0.045 x 9.8˛ x 0.0762 = ~0.329
0.329 = 0.5 x 0.045 x velocity˛
0.5 x 0.045 = 0.0225
0.329 ÷ 0.0225 = ~14.623
0.5 x 0.045 x 14.623 = ~0.329
0.329 x 0.329 = ~0.108 joules

Supermouse level

The trees
Windshear cuts through two trees, but in two different blows.

Shear strength of black ash wood: 5.25 J/cc
Density of black ash wood: 33 lb/ft³, equivalent to ~0.528 g/cc.
Diameter of the tree trunk: ~5.08 cm
Width of the cut: ~0.1 cm
Volume of the cut: 5.08 x 5.08 x 0.1 = ~2.59 cc

5.25 x 2.59 = 13.5975 J, Rat level

Rating: 5/10


I'm curious: would the trunks actually stay upright like that? Obviously, such a calculation would require lots of complicated things I don't understand, so I'll use a more basic model—how much energy would it take to throw the top half of the tree?

Tree's approximate weight: 5.08 x 5.08 x 1.3 x 0.528 = ~17.7 g.
Let's say that we have to throw the tree 0.15 m.

0.0177 x 9.8˛ x 0.15 = ~2.55

2.55 = 0.5 x 0.0177 x velocity˛
0.5 x 0.0177 = 0.00885
2.55 ÷ 0.00885 = 288
Velocity = 288 m/s

0.5 x 0.0177 x 288 = ~2.55
2.55 x 2.55 = 6.5025 J. So yes, the trees would probably be knocked over, given how Windshear's tail seems to have plenty of extra energy, but perhaps it's just that sharp.

Rating: 6/10


The rocks
By sheer strength (traditional approach)
If half of the rock is pulverized and half is violently fragmented:
The violent fragmentation energy of rock is 69 J/cc
The pulverization energy of rock is 214 J/cc.
69 x 2.5 = 172.5
214 x 2.5 = 535
172.5 + 535 = 707.5

Whew! That's Street level.

Rating: 7/10


By toughness
Fragmentation energy by toughness is 0.22 J/cc.
0.22 x 5 = 1.1 J (Supermous level)

Rating: 7/10

Ventress probably weighs 0.04 kg and flies about 0.27 m.

0.04 x 9.8˛ x 0.27 = ~1.037

1.037 = 0.5 x 0.04 x velocity˛
0.5 x 0.04 = 0.02
1.037 ÷ 0.02 = 51.85
Velocity = 51.85 m/s

0.5 x 0.04 x 51.85 = 1.037
1.037 x 1.037 = ~1.075 J—Supermouse level.

Rating: 7/10

Obi-Wan flies around 10 inches (0.254 m).

0.045 x 9.8˛ x 0.254 = ~1.098

1.098 = 0.5 x 0.045 x velocity˛
0.5 x 0.045 = 0.0225
1.098 ÷ 0.0225 = ~48.8
Velocity = 48.8 m/s

0.5 x 0.045 x 48.8 = 1.098
1.098 x 1.098 = ~1.21 J—Supermouse level.

h = 0.1143 cm
d = 0.05715 cm
m = 0.045 kg

First, find potential energy, or PE:
mass (0.045) x acceleration of gravity (9.8˛) x distance fallen (0.05715) = 0.24699087 joules (I’ll round to 0.25)

PE to velocity:
PE = 0.5 x m x velocity˛
0.25 = 0.5 x 0.045 x velocity˛
0.5 x 0.045 = 0.0225. We know that the PE divided by 0.0225 will equal velocity, so:
0.25 ÷ 0.0225 = 11.1111111111 (I’ll round to 11)
Velocity = 11 m/s

Kinetic energy (KE) of the attack =  0.5 x mass x (velocity)˛
0.5 x 0.045 x 11 = 0.2475
0.2475 x 0.2475 = 0.06125625 joules.

The energy of the attack is 0.06125625 J. Let’s round that to 0.06 J.

Rating: 7/10

The sheer strength (used for fragmentation) of "average" stainless steel is 358 j/cc. Grievous fragments about...
0.16 cm x 0.508 cm = 0.08128 cc

0.08128 cc x 358 j/cc = 29.09824 joules.

Rating: 6/10

She flies about 1 foot—0.3048 meters. Ahsoka probably weighs maybe 0.038 kg.

0.038 x 9.8˛ x 0.3048 = 1.112373696. Let's round to 1.

1 = 0.5 x 0.038 x velocity˛
0.5 x 0.038 = 0.019
1 ÷ 0.019 = 52.6315789474 (round to 52.6)
Velocity = 52.6 m/s

0.5 x 0.038 x 52.6 = 0.9994
0.9994 x 0.9994 = 0.99880036

About 0.999 J (Supermouse level).

Rating: 7/10